Saturday, 29 August 2020

Odd Even number from given Array

Write a program to find Number is a Odd number or Even number using Array.
  import java.util.Scanner;
public class EvenOdd {
	public static void main(String[] args) {
		int even_count=0,odd_count=0;
		Scanner scan = new java.util.Scanner(System.in);
		System.out.println("Enter the Array size: ");
		int size=scan.nextInt();
		int [] number=new int[size];
		System.out.println("Enter the elements of an Array: ");
			for(int i=0;i<size;i++)
            {
				number[i]=scan.nextInt();
			}
			//condition used to identify number is odd or even
			for(int i=0; i<size;i++)	
			{
				if(number[i]%2==0)
				{
				even_count++;
				System.out.println(number[i] + " is Even number");
				}
				else
				{
				odd_count++;
				System.out.println(number[i] + " is odd number");
				}
			}
		System.out.println("Even Number Count of an array:- " + even_count);
		System.out.println("Odd Number Count of an array:- " + odd_count);
	}
}

Output:
Enter the Array size: 
6
Enter the elements of an Array: 
15
96
78
35
62
45
15 is odd number
96 is Even number
78 is Even number
35 is odd number
62 is Even number
45 is odd number
Even Number Count of an array:- 3
Odd Number Count of an array:- 3


  

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