Write a program to find Number is a Odd number or Even number using Array.
import java.util.Scanner;
public class EvenOdd {
public static void main(String[] args) {
int even_count=0,odd_count=0;
Scanner scan = new java.util.Scanner(System.in);
System.out.println("Enter the Array size: ");
int size=scan.nextInt();
int [] number=new int[size];
System.out.println("Enter the elements of an Array: ");
for(int i=0;i<size;i++)
{
number[i]=scan.nextInt();
}
//condition used to identify number is odd or even
for(int i=0; i<size;i++)
{
if(number[i]%2==0)
{
even_count++;
System.out.println(number[i] + " is Even number");
}
else
{
odd_count++;
System.out.println(number[i] + " is odd number");
}
}
System.out.println("Even Number Count of an array:- " + even_count);
System.out.println("Odd Number Count of an array:- " + odd_count);
}
}
Output:
Enter the Array size:
6
Enter the elements of an Array:
15
96
78
35
62
45
15 is odd number
96 is Even number
78 is Even number
35 is odd number
62 is Even number
45 is odd number
Even Number Count of an array:- 3
Odd Number Count of an array:- 3
- Write a program to find Number is a Odd number or Even number in simple way.
- Identify Odd or Even Number in a way is using bit-wise Operator.
- Write a program to find Number is a Odd number or Even number using Array.
- Write a program to find Number is a Odd number or Even number from 1 to N.
- Write a program to find Number is a Odd number or Even number From Given Range.
-
Write a program to find Number is a Odd or Even from 1 to N using while loop.
- Write a program to find Number is a Odd or Even from 1 to N using do-while loop.

No comments:
Post a Comment
If you have any doubts, please let me know