Write a Java Program to find given number is Leap or Not using Nested if statement
import java.util.Scanner;
public class Leap
{
public static void main(String[] args)
{
Scanner s = new Scanner(System.in);
System.out.println("Enter Year: ");
int year = s.nextInt();
if ( year % 4 == 0)
{
if (year%100 == 0)
{
if(year%400 == 0)
{
System.out.println("\n"+year+" is a Leap Year. ");
}
else
{
System.out.println("\n"+year+" is a NOT Leap Year.");
}
}
else
{
System.out.println("\n"+year+" is a Leap Year. ");
}
}
else
{
System.out.println("\n"+year+" is a NOT Leap Year. ");
}
}
}
Output:
Enter Year:
2010
2010 is a NOT Leap Year.
Bhut shi
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