import java.util.Scanner;
public class ArmstrongMethod
{
void Amg(int n)
{
int reminder,amstrong=0,temp=n;
while(n!=0)
{
reminder=n%10;
amstrong=amstrong+reminder*reminder*reminder;
n=n/10;
}
if(temp==amstrong)
System.out.println("\n"+temp+" is an amstrong number");
else
System.out.println("\n"+temp+" is not an amstrong number");
}
public static void main(String[] args)
{
AmstrongMethod obj = new AmstrongMethod();
Scanner scan = new Scanner(System.in);
System.out.println("\nEnter a Number: ");
int n = scan.nextInt();
obj.Amg(n);
}
}
OUTPUT:
Enter a Number:
591
591 is not an amstrong number
OUTPUT 2:
Enter a Number:
370
370 is an amstrong number
Basic Java programs. All programs done in very simple ways. It helps beginners to grow their programming skills and build a programming logic.
Friday, 11 December 2020
Armstrong number using Method
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What programming language did you use on this program please?
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