Write a program to find Number is a Positive number or Negative number.
The following concept will test weather; a number is positive or negative. It is done by checking where the number lies on the number line.
Input: Enter Any Number
If Number = 53
Output = Number is Positive
If Number = -89
Output = Number is Negative
Code in C:
#include<stdio.h>
int main()
{
int number;
printf("Insert any number: ");
scanf("%d", &number);
//Logic: Condition to check if the number is negative or positive
if (number == 0)
{
printf("The number is neither Negative nor Positive; number is Zero 0.");
}
else if (number <0)
{
printf("The number is negative");
}
else
{
printf("The number is positive");
}
}
Code in C++:
#include<iostream>
using namespaces std;
int main()
{
int number;
cout<<"Insert any number: ";
cin>>number;
//Logic: Condition to check if the number is negative or positive
if (number == 0)
{
cout<<"The number is neither Negative nor Positive; number is Zero 0.";
}
else if (number <0)
{
cout<<"The number is negative";
}
else
{
cout<<"The number is positive";
}
}
Code in Java:
import java.util.Scanner;
public class positiveandnagative {
public static void main(String[] args) {
Scanner scan = new java.util.Scanner(System.in);
System.out.println("Enter the number: ");
int number=scan.nextInt();
//condition used to identify number
if (number == 0)
{
System.out.println("The number is neither Negative nor Positive; number is Zero 0.");
}
else if (number < 0)
{
System.out.println("The number is negative");
}
else
{
System.out.println("The number is positive");
}
}
}
output:
Enter the number:
-29
The number is negative
Enter the number:
34
The number is positive
Enter the number:
0
The number is neither Negative nor Positive; number is Zero 0.
No comments:
Post a Comment
If you have any doubts, please let me know